-16t^2+224t=640

Solution for -16t^2+224t=640 equation:

-16t^2+224t=640

We move all terms to the left:

-16t^2+224t-(640)=0

a = -16; b = 224; c = -640;
Δ = b2-4ac
Δ = 2242-4·(-16)·(-640)
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9216}=96$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(224)-96}{2*-16}=\frac{-320}{-32}
=+10
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(224)+96}{2*-16}=\frac{-128}{-32}
=+4
$